The great confusion with this class is in its naming. ArrayObject infers it will behave as an Array and as an Object. It won't. It behaves as an array. It would better be called ArrayType. You can, with some work, get it to work both as an object and as an array, but that is up to you.
ArrayObject::__construct
(PHP 5 >= 5.1.0)
ArrayObject::__construct — Constrói um novo objeto array
Valor Retornado
Não há valor retornado.
Exemplos
Exemplo #1 Exemplo de ArrayObject::__construct()
<?php
$array = array('1' => 'um',
'2' => 'dois',
'3' => 'três');
$arrayobject = new ArrayObject($array);
var_dump($arrayobject);
?>
O exemplo acima irá imprimir:
object(ArrayObject)#1 (3) {
[1]=>
string(2) "um"
[2]=>
string(4) "dois"
[3]=>
string(4) "três"
}
ArrayObject::__construct
ashley at nospam dot zincdigital dot com
03-Jul-2009 10:18
03-Jul-2009 10:18
kjarli at gmail dot com
03-Jul-2008 10:11
03-Jul-2008 10:11
This extend allows multidimensional arrays to be converted aswell. It also returns 'Array' when echoed (unlike ArrayObject which gives an error).
<?php
/**
* @author iltar van der berg
* @version 1.0.1
*/
class RecursiveArrayObject extends ArrayObject
{
/**
* overwrites the ArrayObject constructor for
* iteration through the "array". When the item
* is an array, it creates another self() instead
* of an array
*
* @param Array $array data array
*/
public function __construct(Array $array)
{
foreach($array as $key => $value) {
if(is_array($value)){
$value = new self($value);
}
$this->offsetSet($key, $value);
}
}
/**
* returns Array when printed (like "echo array();")
* instead of an error
*
* @return string
*/
public function __ToString()
{
return 'Array';
}
}
?>
german dot rumm at gmail dot com
14-Mar-2008 06:37
14-Mar-2008 06:37
BTW, if you need to change array later, use exchangeArray() method. Good to know when you are writing a class that extends ArrayObject()
AFAIK, exchangeArray() doesn't return anything.
<?php
$a = array('one', 'two', 'three');
$ao = new ArrayObject($a);
foreach ($ao as $element) {
echo $element . ' '; // one two three
}
$b = array('four', 'five', 'six');
$ao->exchangeArray($b); // returns null
foreach ($ao as $element) {
echo $element . ' '; // four five six
}
?>
agalkin at agalkin dot ru
21-Aug-2007 08:56
21-Aug-2007 08:56
Note that the first argument to ArrayObject::__construct, the initial array, is passed by reference. Nevertheless, modification of the array doesn't modify the object, so it may cause unexpected behaviour.
<?php
$array = array('foo' => 'initial');
$obj = new ArrayObject($array);
// array was passed by reference:
$obj['foo'] = 'modified';
var_dump($array); // foo => modified
// but it doesn't work backwards:
$array['foo'] = 'modified_again';
var_dump($obj); // foo => modified
var_dump($array); // foo => modified_again
?>
Grigori Kochanov
15-Jul-2006 10:51
15-Jul-2006 10:51
As Marcus explained, the flag ArrayObject::SPL_ARRAY_AS_PROPS means the array element may be used as a property if there is no conflict with visible properties.
If there are visible properties in the class, the array element will not overwrite it's value.
<?php
class Rules extends ArrayObject {
public $len = 1;
function __construct($array){
parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
$this['len'] = 2;
}
}
$x = new Rules(array(1,2));
echo $x->len;
?>
Result: 1
<?php
class Rules extends ArrayObject {
private $len = 1;
function __construct($array){
parent::__construct($array,ArrayObject::ARRAY_AS_PROPS);
$this['len'] = 2;
}
}
$x = new Rules(array(1,2));
echo $x->len;
?>
Result: 2
