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is_nan> <is_finite
[edit] Last updated: Fri, 25 May 2012

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is_infinite

(PHP 4 >= 4.2.0, PHP 5)

is_infinite値が無限大であるかどうかを判定する

説明

bool is_infinite ( float $val )

val が(正または負の)無限大である場合に TRUE を返します。たとえば log(0) の結果、 あるいはこのプラットフォーム上で扱える float の範囲を超えた数などが あてはまります。

パラメータ

val

調べる値。

返り値

val が無限大である場合に TRUE、 そうでない場合に FALSE を返します。

参考

  • is_finite() - 値が有限の数値であるかどうかを判定する
  • is_nan() - 値が数値でないかどうかを判定する



is_nan> <is_finite
[edit] Last updated: Fri, 25 May 2012
 
add a note add a note User Contributed Notes is_infinite
Anonymous 02-May-2012 04:55
PHP_INT_MAX is The largest integer supported in this build of PHP. Usually int(2147483647). Available since PHP 4.4.0 and PHP 5.0.5
stangelanda at arrowquick dot com 28-Aug-2007 07:29
Actually any string ending in INF is more appropriate than any string beginning with INF.  Since negative infinity evaluates to "-INF" but it is still infinite.  However in either case the STRING "INF" is not infinite, only a float that converts to "INF" or "-INF" is infinite.

A more appropriate function might be:
<?php
if (!is_defined('is_infinite')) { function is_infinite($val) {
    return (
is_float($val) and ("$val"=='INF' or "$val"=='-INF'));
} }
?>
* However the above function is untested.
21-Aug-2006 08:54
@ david,

That will return true for any string ending with "INF".
I think substr("$value",0,3) would be more appropriate.
david(@t)nirvanis(d@t)org 31-Aug-2004 02:49
If you have PHP lower than 4.2 you can simulate the behaviour:

function is_infinite($value) {
   return (substr("$value",-3) == "INF");
}

(tested on php 4.1.2)

 
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