mysqli_stmt::attr_set
dams at php dot net: You can't use this function for getting results, that is what bind_result is for.
I noticed that if you try to use a ? to match a column that doesn't exist, you get a warning that there are too many variables in the bind_param call, for instance:
$stmt->prepare ("INSERT INTO t (badname) VALUES (?)");
$stmt->bind_param("s", $val);
mysqli_stmt::bind_param
mysqli_stmt_bind_param
(PHP 5)
mysqli_stmt_bind_param — Binds variables to a prepared statement as parameters
Description
Object oriented style (method):
Procedural style:
Bind variables for the parameter markers in the SQL statement that was passed to mysqli_prepare().
Note: If data size of a variable exceeds max. allowed packet size (max_allowed_packet), you have to specify b in types and use mysqli_stmt_send_long_data() to send the data in packets.
Parameters
- stmt
-
Procedural style only: A statement identifier returned by mysqli_stmt_init().
- types
-
A string that contains one or more characters which specify the types for the corresponding bind variables:
Type specification chars Character Description i corresponding variable has type integer d corresponding variable has type double s corresponding variable has type string b corresponding variable is a blob and will be sent in packets - var1
-
The number of variables and length of string types must match the parameters in the statement.
Return Values
Returns TRUE on success or FALSE on failure.
Examples
Example #1 Object oriented style
<?php
$mysqli = new mysqli('localhost', 'my_user', 'my_password', 'world');
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$stmt = $mysqli->prepare("INSERT INTO CountryLanguage VALUES (?, ?, ?, ?)");
$stmt->bind_param('sssd', $code, $language, $official, $percent);
$code = 'DEU';
$language = 'Bavarian';
$official = "F";
$percent = 11.2;
/* execute prepared statement */
$stmt->execute();
printf("%d Row inserted.\n", $stmt->affected_rows);
/* close statement and connection */
$stmt->close();
/* Clean up table CountryLanguage */
$mysqli->query("DELETE FROM CountryLanguage WHERE Language='Bavarian'");
printf("%d Row deleted.\n", $mysqli->affected_rows);
/* close connection */
$mysqli->close();
?>
Example #2 Procedural style
<?php
$link = mysqli_connect('localhost', 'my_user', 'my_password', 'world');
/* check connection */
if (!$link) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$stmt = mysqli_prepare($link, "INSERT INTO CountryLanguage VALUES (?, ?, ?, ?)");
mysqli_stmt_bind_param($stmt, 'sssd', $code, $language, $official, $percent);
$code = 'DEU';
$language = 'Bavarian';
$official = "F";
$percent = 11.2;
/* execute prepared statement */
mysqli_stmt_execute($stmt);
printf("%d Row inserted.\n", mysqli_stmt_affected_rows($stmt));
/* close statement and connection */
mysqli_stmt_close($stmt);
/* Clean up table CountryLanguage */
mysqli_query($link, "DELETE FROM CountryLanguage WHERE Language='Bavarian'");
printf("%d Row deleted.\n", mysqli_affected_rows($link));
/* close connection */
mysqli_close($link);
?>
The above example will output:
1 Row inserted. 1 Row deleted.
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User Contributed Notesmysqli_stmt::bind_param
Anonymous
02-Jun-2008 09:04
02-Jun-2008 09:04
dams at php dot net
25-May-2008 11:34
25-May-2008 11:34
don't try to bin twice the same variable, as it won't work.
$query = "select * from table where col1 = ? or col2 = ?";
mysqli_bind_param($stmt, "ss", $arg, $arg);
You have to use a another variable :
$query = "select * from table where col1 = ? or col2 = ?";
$arg2 = $arg;
mysqli_bind_param($stmt, "ss", $arg, $arg2);