Last 5.3 release ever available: PHP 5.3.29 - 5.3 now EOL

session_is_registered

(PHP 4, PHP 5 < 5.4.0)

session_is_registeredFind out whether a global variable is registered in a session

Description

bool session_is_registered ( string $name )

Finds out whether a global variable is registered in a session.

Warning

This function has been DEPRECATED as of PHP 5.3.0 and REMOVED as of PHP 5.4.0.

Parameters

name

The variable name.

Return Values

session_is_registered() returns TRUE if there is a global variable with the name name registered in the current session, FALSE otherwise.

Notes

Note:

If $_SESSION (or $HTTP_SESSION_VARS for PHP 4.0.6 or less) is used, use isset() to check a variable is registered in $_SESSION.

Caution

If you are using $_SESSION (or $HTTP_SESSION_VARS), do not use session_register(), session_is_registered() and session_unregister().

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User Contributed Notes 7 notes

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4
paimpozhil at gmail dot com
1 year ago
For those who have an older application which uses the session_is_registered..and you want to use that in php5.4

You can just define the function if required

function session_is_registered($x)
{
    if (isset($_SESSION['$x']))
    return true;
    else
    return false;
}

May be add the checks to ensure function is not already existing..
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1
someone at the dot inter dot net
5 months ago
A simple one-line function to emulate this in later versions of PHP:
function session_is_registered($x){return isset($_SESSION['$x']);}
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-1
miguel dot simoes at swirve dot com
12 years ago
When using PHP 4.2.0 even on the same page where you registered the variable with:

session_register("someVar");

if you try to see if the variable is set and do not assign it a value before, the function used in the previous comment will give the same output.
This may show that the variable is declared and will not be set until some value is give assign to it.
I think that this way will give the option to register all the variables used for sure on the process on the first page and using them as the time comes.
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-2
amol_bhavsar1982 at hotmail dot com
5 years ago
session_register() function is generating warnings. Therefore, instead of using:

<?php
$test
= 'Here';
session_register('test');
?>

It is better :

<?php
$_SESSION
['test'] = 'Here';
?>
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-1
someone at the dot inter dot net
5 months ago
A simple one-line function to emulate this in later versions of PHP:
function session_is_registered($x){return isset($_SESSION['$x']);}
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-5
Sami
6 months ago
I can not get the following code to work as it is returning an error on the session_is_registered() and do I have to change anything else in the code

Thank you

if(!session_is_registered('user_name')){

if (isset($_POST['username'])) {
$password1 = clean($_POST["password"]);
$username1 = clean($_POST["username"]);
$password2 = crypt($password1);

$result = @mysql_query ("select * from users where user_name = '".$username1."'");
$lim = @mysql_num_rows( $result );
//|| (strlen($username1) < 6) || (strlen($password1) < 6)
if( ($lim!=0)  ){
$row = @mysql_fetch_array($result);
$password=$row['user_password'];
if (crypt($password1, $password) == $password){
$sql = @mysql_query ("insert into logs (ip, cdate, status) values ('".$REMOTE_ADDR."','". date("Y-m-d H:i:s") ."', 'Login')");
session_register('user_id');
session_register('user_fullname');
session_register('user_name');

$_SESSION['user_name'] = $row['user_name'];
$_SESSION['user_fullname'] = $row['user_fullname'];
$_SESSION['user_id'] = $row['user_id'];
}//if crypt
else{
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-10
vectorjohn at example dot com
8 months ago
The proper equivalent has nothing to do with isset().

Use array_key_exists() because session_is_registered returns true if the variable is in the session at all, even if it's falsy.
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